/**
 * A More realistic, but still quite useless, example of function
 * pointers
 * @author gtowell
 * Created: April 2021
 * **/

#include <stdio.h>

/**
 * Apply the operation passed in as a function pointer to the 
 * other params
 * @param f -- a pointer to a function.  The function must return 
 *             an int and it must take two ints as param
 * @param a -- an int
 * @param b -- another int
 * @return the value that result from applying the passed function
 * to the two params
 * **/
int op(int(*f)(int,int), int a,int b) {
    return (*f)(a, b);
}

/**
 * Multiply two integers 
 * @param a an integer
 * @param b another integer
 * @return the product of the two integers
 * **/
int mult(int a, int b) {
    return a * b;
}

/**
 * Divide two integers but go UP if remainder > 0.
 * @param a an integer
 * @param b another integer
 * @return the product of the two integers
 * **/
int div(int a, int b) {
    return  (a / b)  + ((a % b == 0) ? 0 : 1);
}

int main(int argc, char const *argv[])
{
    printf("%d\n", op((*mult),3,4));
    printf("%d\n", op((*div),20,4));
    return 0;
}