/*
 * Simple type conversions from string to int or double
 * 
 * Created: Aug 14, 2023
 * @authou gtowell
 */
public class Convert {
    public static void main(String[] args) {
        String baseString = "5";
        int baseInt = Integer.parseInt(baseString);
        double baseDouble = Double.valueOf(baseString);

        // the point of these lines is to show the binary (0 and 1) representations
        // of int and double for a particular number.
        // 
        // Converting a string to binary is more complex
        double baseDouble2 = baseInt;
        double baseInt2 = baseDouble;
        double d = 55.0;
        System.out.println("Double 55 => " + Long.toBinaryString(Double.doubleToRawLongBits(d)));
        int dd = 55;
        System.out.println("Int    55 => 00000000 00000000 00000000 00" + Integer.toBinaryString(dd));
        String ddd = "55";
        System.out.println("String 55 => " + convertStringToBinary(ddd));
    }

    /*
     * This uses a lots of things that we have not taked about yet.
     * So ignore, for now.
     */
    public static String convertStringToBinary(String input) {
        StringBuilder result = new StringBuilder();
        char[] chars = input.toCharArray();
        for (char aChar : chars) {
            result.append(
                    String.format("%8s", Integer.toBinaryString(aChar))   // char -> int, auto-cast
                            .replaceAll(" ", "0")                         // zero pads
            );
            result.append(" ");
        }
        return result.toString();

    }

}