/**
 * Get 8 3 bit numbers of the command line (ie, number in range 0-7)
 * and output the bit from those three numbers.
 * Either by printing the bits to the screen or by 
 * putting the bits into an unsigned char, then outputiong that 
 * char to the screen every time its gets all 8 bits filled.
 * 
 * 
 * @author gtowell
 * Created: April 2021
 * Modified: May 2021
 * **/

#include <stdio.h>
int main(int argc, char const *argv[])
{
    unsigned char output = 0;
    unsigned int res = 0;
    int b = 0;
    for (int i = 1; i <= 8; i++)
    {
        int num = argv[i][0] - '0';  //atoi(argv[i]);
        for (int j = 0; j < 3; j++)
        {
            /**
             * idea, since I only case about bits in positions 
             * 1,2 and 3 (from right), will read bit in position 3,
             * then shift one to left, read in position 3 again,
             * etc.  Thus get bits out, most significant first.
             * The result of this is the bits some out in order
             * But is feels pretty backward
             * **/
            int v = (num & 4) ? 1 : 0;
            output <<= 1;
            printf("%d", v);
            output |= v;
            num <<= 1;
            b++;
            if (b>=8) {
                printf("\n%d\n", output);
                b = 0;
                output = 0;
            }
        }
    }
    printf("\n");
    return 0;
}